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SSHFP record creation should scan nonstandard SSH port if necessary (#974)

* sshfp records from nonstandard ports

If port 22 is not open, dns_update.py will not create SSHFP records
because it only scans port 22 for keys. This commit modifies
dns_update.py to parse the sshd_config file for open ports, and
then obtains keys from one of them (even if port 22 is not open).

* modified test of s per JoshData request

* edit CHANGELOG per JoshData

* fix typo
This commit is contained in:
rxcomm 2016-10-15 14:36:13 -05:00 committed by Joshua Tauberer
parent a658abc95f
commit bbe27df413
2 changed files with 13 additions and 1 deletions

View File

@ -8,6 +8,7 @@ Control panel:
* Remove recommendations for Certificate Providers * Remove recommendations for Certificate Providers
* Status checks failed if the system doesn't support iptables * Status checks failed if the system doesn't support iptables
* Add support for SSHFP records when sshd listens on non-standard ports
v0.20 (September 23, 2016) v0.20 (September 23, 2016)
-------------------------- --------------------------

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@ -348,7 +348,18 @@ def build_sshfp_records():
# like the known_hosts file: hostname, keytype, fingerprint. The order # like the known_hosts file: hostname, keytype, fingerprint. The order
# of the output is arbitrary, so sort it to prevent spurrious updates # of the output is arbitrary, so sort it to prevent spurrious updates
# to the zone file (that trigger bumping the serial number). # to the zone file (that trigger bumping the serial number).
keys = shell("check_output", ["ssh-keyscan", "localhost"])
# scan the sshd_config and find the ssh ports (port 22 may be closed)
with open('/etc/ssh/sshd_config', 'r') as f:
ports = []
t = f.readlines()
for line in t:
s = line.split()
if len(s) == 2 and s[0] == 'Port':
ports = ports + [s[1]]
# the keys are the same at each port, so we only need to get
# them at the first port found (may not be port 22)
keys = shell("check_output", ["ssh-keyscan", "-p", ports[0], "localhost"])
for key in sorted(keys.split("\n")): for key in sorted(keys.split("\n")):
if key.strip() == "" or key[0] == "#": continue if key.strip() == "" or key[0] == "#": continue
try: try: